- أكتوبر 17, 2013
- منشور من طرف: فريق ويكي الفوركس
- فئة: FX Ind
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مؤلف: | ميتاكوتس (2008.02.10 15:45) | ||
تم التنزيل: | 4699 | ||
تحميل: |
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Indicator Smoothed ADX was written on demand of a forum visitor and was not too difficult. لكن, the search for a description of the smoothed ADX algorithm resulted in nothing. This is why I give below only the code that has been provided: المدخلات: {declaring inputs} variables: {declaring variables}
DMIPlus( 0 ), DMIMinus( 0 ), DMI( 0 ), ADX( 0 ), DIPlusLead(0), DIMinusLead(0), DIPlusFinal(0), DIMinusFinal(0), ADXLead(0), ADXFinal(0); {now calling the built-in ADX functions, so we don't need to calculate them}
Value1 = DirMovement( ح, ل, ج, Length, DMIPlus, DMIMinus, ADX);
{this part is the actual smoothing of the original ADX indicator, DI+, DI- and ADX lines are smoothed}
DIPlusLead = 2*DMIPlus + (alpha1 - 2) * DMIPlus[1] + (1 - alpha1) * DIPlusLead[1];
DIPlusFinal = alpha2*DIPlusLead + (1 - alpha2) * DIPlusFinal[1]; DIMinusLead = 2*DMIMinus + (alpha1 - 2) * DMIMinus[1] + (1 - alpha1) * DIMinusLead[1];
DIMinusFinal = alpha2*DIMinusLead + (1 - alpha2) * DIMinusFinal[1]; ADXLead = 2*ADX + (alpha1 - 2) * ADX[1] + (1 - alpha1) * ADXLead[1];
ADXFinal = alpha2*ADXLead + (1 - alpha2) * ADXFinal[1]; {Plotting them on chart}
Plot1( DIPlusFinal, "DMI+" ) ;
Plot2( DIMinusFinal, "DMI-" ) ;
Plot3( ADXFinal, "ADX" ) ;
أو, in a different way: Vol(ص) = 8*P0 - 7P1 - Ehlers' burst (the term is invented by myself). At the second stage, we apply the simple weighted smoothing: W0 = (1*V0 + 2*W1) / (2 + 1).
In Smoothed ADX, this smoothing algorithm is applied to all three buffers of standard indicator ADX. This is why the obtained indicator is called Smoothed ADX. If we were smoothing indicator RSI, we would call it Smoothed RSI, إلخ. The figure below shows that Smoothed ADX, indeed, is not so 'twitchy' as the original, standard ADX (Average Directional Movement Index).
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1 تعليق لنشر تعليق جديد, لو سمحت تسجيل الدخول أو يسجل
This is a reallly good indicator. Thanks Rosh! I have one question. How would I compare the current ADXFinal value with the ADXFinal value 3 periods ago? Shouldn't it already be housed in the array? لو ذلك, أين? I the array count down confused me a bit as it's been a long time since I've coded. TIA. |